IDF V4.3 beta 1
I'm just going through the UART functions and structs. I noticed that there is a uart_sw_flowctrl_t struct that has threshold and both xon and xoff characters.
https://docs.espressif.com/projects/esp ... lowctrl_t
On the other hand, there is no function that uses this struct. The only function related is the uart_set_sw_flow_ctrl() that does NOT have the xon or xoff characters:
https://docs.espressif.com/projects/es ... _t7uint8_t
I also checked the source code. This uart_sw_flowctrl_t struct is not even defined let alone used. So is this planned, already implemented in latest or else? Thanks.
How to set UART xon xoff characters?
Re: How to set UART xon xoff characters?
The struct is used in the uart.c file when calling the SW Flow Conrol function.
It doesn't mean that you can determine the xon and xoff characters.
The XON and XOFF are defined as the default ASCII characters 0x13 and 0x11 just as the UART protocol describes
Code: Select all
esp_err_t uart_set_sw_flow_ctrl(uart_port_t uart_num, bool enable, uint8_t rx_thresh_xon, uint8_t rx_thresh_xoff)
{
ESP_RETURN_ON_FALSE((uart_num < UART_NUM_MAX), ESP_FAIL, UART_TAG, "uart_num error");
ESP_RETURN_ON_FALSE((rx_thresh_xon < SOC_UART_FIFO_LEN), ESP_FAIL, UART_TAG, "rx flow xon thresh error");
ESP_RETURN_ON_FALSE((rx_thresh_xoff < SOC_UART_FIFO_LEN), ESP_FAIL, UART_TAG, "rx flow xoff thresh error");
uart_sw_flowctrl_t sw_flow_ctl = {
.xon_char = XON,
.xoff_char = XOFF,
.xon_thrd = rx_thresh_xon,
.xoff_thrd = rx_thresh_xoff,
};
UART_ENTER_CRITICAL(&(uart_context[uart_num].spinlock));
uart_hal_set_sw_flow_ctrl(&(uart_context[uart_num].hal), &sw_flow_ctl, enable);
UART_EXIT_CRITICAL(&(uart_context[uart_num].spinlock));
return ESP_OK;
}
The XON and XOFF are defined as the default ASCII characters 0x13 and 0x11 just as the UART protocol describes
Code: Select all
#define XOFF (0x13)
#define XON (0x11)
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